Since it's a linear graph, the graph will cut the x and y-axis once and once only.
Now, we can find where the x and y-intercepts are located.
x-intercept is found when we substitute y as 0.



Thus, we know that the point (-4, 0) will pass through the graph.
Now, similarly, to find the y-intercept, we let x = 0.


Thus, we know that the point (0, 2) will pass through the graph.
We also know it has a positive gradient, so just join the dots to find the graph's shape.
Refer to <span>Herontewodros for the correct graph.</span>