Answer:
74.73%
Step-by-step explanation:
First, we're gonna find out her total amount
We're gonna use the count interest formula: P = A(1 + r)ⁿ
P = final amount
A = starting amount (1300)
r = rate (0.06)
n = years (5)
P = 1300(1 + 0.06)⁵
P = 1739.693251
Now divide the starting amount by the total amount
1300 ÷ 1739.693251 = 0.7472582
Answer:
-2/-5
none of the option is correct
Same as the car one
A=Pe^(rt)
when it is a decay, make r negative
P=23781 and r=-0.032 and t=17
A=23781e^(-0.032*17)
A=23781e^(-0.554)
A=13803.01
so about 13803 people is the population after 17 years
for these you need to rearrange the equations and do substitutions.
#3 = if x+y=5 then you know x = 5-y
now substitute that equation for x in the 2nd one so x + 2y = 8 becomes
5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3
now replace y with 3 in the first equation x = 5-3 so x = 2
so (2,3) is the answer
same type of work for #4
2x-y=6 ,S0 y = 2X+6
so now you have 4x+2(2x+6)=-4
that becomes 4x +4x+12 = -4
8x+8 = 1, x =1
y = 2(1)-6 = -4
so answer is (1,-4)
Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
_____
The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.
