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RSB [31]
3 years ago
6

What are the domain range of f(x)= 1/5 power of x

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

I'm assuming you mean the function f(x)=x^{\frac{1}{5}}.  That's usually written

f(x) = x^(1/5) with the ^ meaning "to the power of..." and the fraction exponent in parentheses so as not to be confused with x^1/5 which could mean x to the first power, divided by 5.

Fractional exponents are used to indicate roots.  In this case, x is being raised to the 1/5 power, so this is the fifth root of x, written \sqrt[5]{x}.  The 5 is called the root index.

For odd roots, like this one, the domain is all real numbers--<em>x</em> can be any number at all.  So the domain is all real numbers.

The range is also all real numbers.  Attached is a graph of this function. It might not look like it, but the graph rises to the right to any height.  The larger <em>x</em> gets, the larger the 5th root gets.  A similar thing happens on the left--the smaller <em>x</em> gets, the smaller the 5th root gets.

EDIT: see the comment.  For the function f(x)=(1/5)^x, the domain is all real numbers. The range is positive real numbers.  I'll attach a graph!

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Answer:x=1.5

Step-by-step explanation:

Given

Two points co-ordinates are given

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let other point be C =(x,y)

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A=\begin{vmatrix}5& -8&1\\5& 4&1\\x& y&1\end{vmatrix}

A=5\left ( 4-y\right )+8\left ( 5-x\right )+1\left ( 5y-4x\right )

A=20-5y+40-8x+5y-4x

A=60-8x

and A=48 square unit

48=60-8x

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As area is independent of y therefore at x=1.5 any value of y will give area of 48 square unit

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