Answer:

And when we apply the limit we got that:

Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:

We can express this formula like this:
![\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7Di%5E3%20%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
![\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
If we operate and we take out the 1/4 as a factor we got this:

We can cancel
and we got

We can reorder the terms like this:

We can do some algebra and we got:

We can solve the square and we got:

And when we apply the limit we got that:

Answer: Jimmy has 20 more apples than Karl.
Step-by-step explanation:
40 - 20 = 20
Answer:
The -1 came from factoring.
The equation is multiplied by 8 because 8 could be pulled from 16x-8.
16 can be divided by 8 2 times and 8 can only divided by 8 once.
so factoring it makes the equation 8(2x-1)
Answer:
a) m∠FGH= 28°
b) m∠HGI = 28°
c) m ∠FGI = 56°
Step-by-step explanation:
GH bisects ∠FGI. So, ∠FGH = ∠HGI
5x - 2 = 6x -8
5x - 6x = 2 - 8
-x = - 6
x = 6
a) m∠FGH = 5x - 2 = 5 * 6 - 2 = 30 - 2 = 28°
b) m∠HGI = 6x - 8 = 6 * 6 - 8 = 36 - 8 = 28°
c) m ∠FGI = m∠FGH + m∠HGI = 28° +28° = 56°
Any irrational number produces an irrational number when added to 3/4.
This is because 3/4 is rational (it can be represented as a ratio of two integers). You can get an irrational number only when you add rational to irrational (because rational to rational produces a rational sum).