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2 years ago

Where did we get one?

Mathematics

1 answer:

77julia77 [94]2 years ago

5 0

Answer:

The -1 came from factoring.

The equation is multiplied by 8 because 8 could be pulled from 16x-8.

16 can be divided by 8 2 times and 8 can only divided by 8 once.

so factoring it makes the equation 8(2x-1)

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3 years ago

About how much does the area of a circle increases when the radius increases from 3cm to 5cm?

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3 years ago

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2 years ago

Arrange the angles in increasing order of their cosines.

Misha Larkins [42]

Answer:

$\pi,\ \dfrac{7\pi}{6},\ \dfrac{3\pi}{4},\ \dfrac{4\pi}{3},\ \dfrac{3\pi}{2},\ \dfrac{5\pi}{3},\ \dfrac{7\pi}{4},\ 2\pi.$

Step-by-step explanation:

Convert each angle in degree measure:

$\dfrac{3\pi}{4}=135^{\circ},\\ \\\pi=180^{\circ},\\ \\\dfrac{7\pi}{6}=210^{\circ},\\ \\\dfrac{5\pi}{3}=300^{\circ},\\ \\\dfrac{7\pi}{4}=315^{\circ},\\ \\\dfrac{4\pi}{3}=240^{\circ},\\ \\\dfrac{3\pi}{2}=270^{\circ},\\ \\2\pi=360^{\circ}.$

Then

$\cos \dfrac{3\pi}{4}=\cos 135^{\circ}=-\dfrac{\sqrt{2}}{2},\\ \\\cos \pi=\cos 180^{\circ}=-1,\\ \\\cos \dfrac{7\pi}{6}=\cos 210^{\circ}=-\dfrac{\sqrt{3}}{2},\\ \\\cos \dfrac{5\pi}{3}=\cos 300^{\circ}=\dfrac{1}{2},\\ \\\cos \dfrac{7\pi}{4}=\cos 315^{\circ}=\dfrac{\sqrt{2}}{2},\\ \\\cos \dfrac{4\pi}{3}=\cos 240^{\circ}=-\dfrac{1}{2},\\ \\\cos \dfrac{3\pi}{2}=\cos 270^{\circ}=0,\\ \\\cos 2\pi=\cos 360^{\circ}=1.$

Therefore, the angles in increasing order of their cosines are

$\pi,\ \dfrac{7\pi}{6},\ \dfrac{3\pi}{4},\ \dfrac{4\pi}{3},\ \dfrac{3\pi}{2},\ \dfrac{5\pi}{3},\ \dfrac{7\pi}{4},\ 2\pi.$

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3 years ago

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