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3 years ago

Determine whether the lines are parallel or perpendicular or neither. 2x=y−10 and y=−2x

Mathematics

1 answer:

MrRa [10]3 years ago

7 0

Put the first equation in slope-intercept form, or y = mx + b. Start by subtracting y from both sides.

2x - y = -10, subtract 2x from both sides.

-y = -10 - 2x

Divide both sides by negative one.

y = 10 + 2x

To find the slope when the equations are in slope-intercept form you look at the coefficient of x. The first equation has the slope of 2 (which we just found), and the second equation has the slope of -2.

Parallel lines have the same slope and perpendicular lines have opposite reciprocal slopes. Since 2 and -2 are neither of these, your answer is neither.

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320 rounded to the nearest ten

Simora [160]

Answer:

320

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of $\frac{5}{6}$ kilogram of candy is $7.5

- We need to find the cost of $4\frac{5}{7}$ kilogram

We can use the ratio to find the answer

======= Dollar : Kilogram

======= 7.5 : $\frac{5}{6}$

======= c : $4\frac{5}{7}$

By using cross multiplication

∴ c × $\frac{5}{6}$ = 7.5 × $4\frac{5}{7}$

∵ $4\frac{5}{7}$ = $\frac{4*7+5}{7}$

∴ $4\frac{5}{7}$ = $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = 7.5 × $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = $\frac{495}{14}$

Divide both sides by $\frac{5}{6}$

∴ c = $\frac{495}{14}$ ÷ $\frac{5}{6}$

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = $\frac{495}{14}$ × $\frac{6}{5}$

∴ c = $\frac{297}{7}$ = 42.43 dollars

∵ c represents the cost of $4\frac{5}{7}$ kg

∴ It costs $42.43

7 0

3 years ago

This question is down below. The picture attached below. <br> Thanks.

Ostrovityanka [42]

The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Given an equation showing profits of A Christmas vendor as

P=-0.1 $g^{2}$ +30g-1200.

We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.

To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.

665.60=-0.1 $g^{2}$ +30g-1200

0.1 $g^{2}$ -30g+1200+665.60=0

0.1 $g^{2}$ -30g+1865.60=0

Divide the above equation by 0.1.

$g^{2}$ -300g+18656=0

Solving for g we get,

g=[300± $\sqrt{(300)^{2}-4*1*18656 }$ ]/2*1

g=[300± $\sqrt{90000-74624}]/2$

g=[300± $\sqrt{15376}$ ]/2

g=(300±124)/2

g=(300+124)/2 , g=(300-124)/2

g=424/2, g=176/2

g=212,88

Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.

Put the value of P=1500 in equation P=-0.1 $g^{2}$ +30g-1200.

-0.1 $g^{2}$ +30g-1200=1500

0.1 $g^{2}$ -30g+1500+1200=0

0.1 $g^{2}$ -30g+2700=0

Dividing equation by 0.1.

$g^{2}$ -300g+27000=0

Solving the equation for finding value of g.

g=[300± $\sqrt{300^{2} -4*1*27000}$ ]/2*1

=[300± $\sqrt{90000-108000}] /2$

=[300± $\sqrt{-18000}$ ]/2

Because $\sqrt{-18000}$ comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.

Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Learn more about equation at brainly.com/question/2972832

#SPJ1

7 0

1 year ago

Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord

Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.