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o-na
[289]
3 years ago
8
In a different plan for area codes, the first digit could be any number from 4 through 7, the second digit was either 2, 3, or
4, and the third digit could be any number except 0 . With this plan, how many different area codes are possible?
Mathematics
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answer:
adell
[148]
3 years ago
8
0
1st digit:: 3ways
2nd digit:: 3ways
3rd digit:: 9 ways
3x3x9=81
So the answer is 81 different possible area codes.
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