Given the sequence below, what is the 9th term? 2, 1, 4, -1, 6, ...

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

The 9th term would be 10.

Step-by-step explanation:

Each of the odd terms is 2 more than the previous. We do not even need to look at the even terms to find the 9th one.

2, odd, 4, odd, 6, odd, 8, odd, 10

You might be interested in

Using PEMDAS solve<br> 22/2x3

emmainna [20.7K]

22/2 = 11
11 x 3 = 33

7 0

3 years ago

Read 2 more answers

Help me. i swear... if u dont. u are an uncultured swine

igor_vitrenko [27]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use the rules of inference to prove the conclusion r given (all 1,2,3 and 4) the four premises listed below. Write your solution

aniked [119]

Answer:

attached below

Step-by-step explanation:

Applying the rule of logical equivalences

attached below is a detailed solution ( written as a numbered sequence of statements )

3 0

3 years ago

Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premiu

AnnZ [28]

Premium rates are usually for premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202

<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
Thus, we have p = 6.01, y = 1000

Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

$\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun$