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matrenka [14]
2 years ago
8

Write the ratio 36 computers for every 6 students in 3 ways

Mathematics
1 answer:
rjkz [21]2 years ago
6 0

Answer:

Step-by-step explanation:

Lol

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using a number line, find both the intersection and the union of the following interval: (-∞, 7) and [-5, +∞)
Gwar [14]

Step-by-step explanation:

the intersection of the interval: (-∞, 7) and [-5, +∞)

is [-5, 7)

and the union of the interval: (-∞, 7) and [-5, +∞)

is (-oo, +oo)

7 0
3 years ago
What statement best demonstrates why the following is a NON-EXAMPLE of a polynomial?
madreJ [45]

Answer:

D

Step-by-step explanation:

If a function has x in the denominator, it cannot be a polynomial.

The rest of the options either don't apply to the equation, or are not rules for polynomials.

5 0
2 years ago
Can an octagon have interior angles that measure 100 degrees, 156 degrees, 125 degrees, 90 degrees, 175 degrees, 160 degrees, an
worty [1.4K]

9514 1404 393

Answer:

  yes

Step-by-step explanation:

The 7 angles listed have a total of 946 degrees. The total interior angle measure in an octagon is 1080 degrees. So, the remaining angle must have a measure of 134°. The figure is entirely feasible.

4 0
2 years ago
3. Jessie is looking for the volume of the cone
Llana [10]

Answer:

A

Step-by-step explanation:

The base is the circle.

To find the area of the circle, use pi*r^2

pi = 3.14

r = 6

  • Area = 3.14 * 6^2
  • Area = 3.14 * 36
  • Area = 113.04

6 0
3 years ago
Read 2 more answers
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

  • Length of the Larger Rectangle =80+2w
  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
3 years ago
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