Answer:
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
Explanation:
If two heterozygous individuals have a child
i.e let the heterozygous individuals be = Xy
if both traits crosses together; their F₁ offspring will be; (XX, Xy, Xy, yy)
Xy × Xy
X y
X XX Xy
y Xy yy
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
Answer:
the only one thats wrong is increased drought
Explanation:
the 3 answers are increased sea level, increased rainfall, and increased agricultural irrigation
Answer:
need to be done with plenty of observation to avoid infection.
Explanation:
This technique is quite delicate because the main risk is infection. Some of the main risks are neuromuscular disease, sedation or neurological illness.
Another risk is that by passing the time, there is a difficult in respiratory, in this case, the main risk is directly to the heart, with some stoke, due to the high concentration of carbon dioxide due to the low exchange among oxygen and CO2.
Some of the indications are:
a.- Coarse crackles auscultated over trachea.
b.- Increase the respiratory pressure.
c.- Decrease tidal volume.
d.- Check the levels of oxygen in blood as in arteries.
e.- Check that patients can generate a cough.
Hope this info is useful.
Answer:
B. The 55 N cat has less mass than the 110 N dog.
Explanation:
Weight of an object refers to the product of its mass and the force of gravity. However, the greater that mass of an object, the greater the weight of that object.
In this case, the cat's weight is 55N while the dog's weight is 110N. This means that the dog has a greater mass than the cat or alternatively put, the 55 N cat has less mass than the 110 N dog.
Note that: if the gravitational effect is removed, the cat will contain lesser mass.
