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lions [1.4K]
4 years ago
6

______are reactants in the process of cell respiration

Biology
2 answers:
xxMikexx [17]4 years ago
7 0

Answer:

Oxygen and glucose are reactants in the process of cell respiration.

Explanation

In the cellular respiration, Glucose is required in the formation of ATP whereas oxygen is required for the converting glucose into ATP. One glucose molecules gives 2 ATP.

In other living beings oxygen enters when we breath but glucose enters when we eat something. One molecule of glucose and 6 molecules of oxygen gives 6 molecules ofCO_2 and 6 molecules of water.

The chemical reactions is as follows:

  C_6H_12O_6  +  6O_2  =>    6CO_2  + 6H_2O

Evgen [1.6K]4 years ago
4 0

Answer:

The reactants are the Products of Photosynthesis which is glucose and oxygen.

C_{6}H_{12}O_{6}+60_{2}

Explanation:

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Bob, a nutritionist who works for the university medical center, has been asked to prepare special diets for two patients, susan
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Answer and Explanation:

Possibly, you forgot to attach the table with the contents of each food. Therefore, I calculated the task with similar values.

1. <em>Assume you have Food A, B, and C. Each has certain amount of Calcium, Iron, and Vit C. </em>

<em>             </em>Let's designate: Calcium <em>→ X oz , Iron → Y oz, vit C → Z oz</em>

2. <em>Assume you have following amount of</em><em> Calcium</em><em> in each food: </em>

  • Food A = 30 mg/oz
  • Food B = 25 mg/oz
  • Food C = 20 mg/oz

3. <em>Assume you have following amount of</em><em> Iron </em><em>in each food: </em>

  • Food A = 1 mg/oz
  • Food B = 1 mg/oz
  • Food C = 2 mg/oz

4. <em>Assume you have following amount of</em><em> vit C </em><em>in each food: </em>

  • Food A = 2 mg/oz
  • Food B = 5 mg/oz
  • Food C = 4 mg/oz

<u>Calculations:</u>

→ You have 3 different food and each has Calcium in it. You need exactly 320mg of Calcium per day. Therefore, each food would comprise certain proportion of daily Calcium intake. We can come up with equation: 30X+25Y+20Z = 390 mg

  • Similarly, for iron and vitamin C, the next equations could be used:

        X+Y+2Z=17 - Iron

        2X+5Y+4Z=42 - Vit C

→ Now you have a system of equations:

30X+25Y+20Z = 390 <em>(1) </em>

X+Y+2Z=17 <em>(2)</em>

2X+5Y+4Z=42 <em>(3)</em>

→ Look for similarities! <em>(1) and (3) </em>seem to be similar. We can multiply the <em>(3) </em>by -5 to obtain: -10X-25Y-20Z=-210. We add the <em>(1)</em> and modified <em>(3)</em> equations.

30X+25Y+20Z = 390

-10X-25Y-20Z=-210

__________________

20X+0+0=180

20X=180

<em><u>→ X=9 (oz of Calcium)</u></em>

<em><u></u></em>

→ Now, we can put<em> x=9 </em>into equations above to ease our job:

270+25Y+20Z=390 → 25Y+20Z=390-270=120

9+Y+Z=17 → Y+2Z=17-9=8

18+5Y+4Z=42 → 5Y+4Z=42-18=24

→ Similarly, we can use Eq-s <em>(2) and (3). </em>We can multiply the <em>(2) </em>by -5 to obtain: -5Y-10Z=-40. We add the <em>(3)</em> and modified <em>(2)</em> equations.

-5Y-10Z=-40

5Y+4Z=24

__________________

-6Z=-24

Z=4

<em><u>→ Z=4 (oz of vit C)</u></em>

<em><u></u></em>

→ Now, we can take X+Y+Z=17 <em>(2) </em>and just put in known values(<em>X=9 and Z=4</em>) to obtain Y:

9+Y+4=17

<u>→ Y=17-9-4=4 (oz of Iron)</u>

<u></u>

That's all! So, if you have table values, you can just re-write the equations and doing it stepwise, as it is shown here, you can manage to calculate every value you need :)

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