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Ulleksa [173]
3 years ago
7

The safety rules for a playground state that the height of the slide and the distance from the base of the ladder to the front o

f the slide must be in a ratio of 3 : 5. What would be the length of this slide? Round your answer to the nearest whole number. ____feet

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer: 12

Step-by-step explanation: c = √a2 + b2

= √(6)2 + (10)2

= √36 + 100

= √136

= 2√34

= 11.661903789691

Round up

12

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stellarik [79]

Answer:

x=3

Step-by-step explanation:

Given,

1 = 1/(x-2)

Multiply both sides by (x-2),

1*(x-2) = 1/(x-2) * (x-2)

x-2 = 1

Adding 2 on both sides,

x-2+2 = 1+2

x = 3

6 0
3 years ago
Rotate rectangle ABCD 90ºccw about the origin. What<br> are the image coordinates?
bazaltina [42]

Answer:

Step-by-step explanation:

1. When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.

2. The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .

3. Rotation of a point through 180°, about the origin when a point M (h, k) is rotated about the origin O through 180° in anticlockwise or clockwise direction, it takes the new position M' (-h, -k). ...

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3 years ago
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
What is the discount on a pair of shoes with a regular price of $48?
Korolek [52]
The discounts on a pair of shoes with a regular price of $48 is 24
8 0
2 years ago
3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e
Stells [14]

Answer:

y=2e^{sin(x)}

Step-by-step explanation:

Given equation can be  re written as

\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating  \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c............(i)

Now it is given that y(π/2) = 2e

Applying value in (i) we get

ln(2e) = sin(π/2) + c

=> ln(2) + ln(e) = 1+c

=> ln(2) + 1 = 1 + c

=> c = ln(2)

Thus equation (i) becomes

ln(y) = sin(x) + ln(2)

ln(y) - ln(2) = sin(x)

ln(y/2) = sin(x)

y= 2e^{sinx}

7 0
3 years ago
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