Allan and Robert are viewing a kite in the air. The kite

Mathematics

1 answer:

bogdanovich [222]2 years ago

5 0

$tan \: a = \frac{opp}{adj} = \frac{205}{adj}$

$adj = \frac{205}{ \tan(35) }$

$adj = 292.7703414$

$tan \: r = \frac{opp}{adj} = \frac{205}{adj}$

$adj = \frac{205}{ \tan(51) }$

$adj = 166.0057268$

$292.7703414 + 166.0057268$

$= 458.7760682 \: ft.$

round as you wish.

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Evaluate |c2 + b2|, given a = 5, b = -3, and c = -2.

Helen [10]

Answer:

Step-by-step explanation:

This is the answer because:

1) First, insert all the numbers into the expression

Expression: I -2(2) + -3(2) I

2) Next, do -2 x 2 and -3 x 2

-2 x 2 = -4

-3 x 2 = -6

3) Then, do -4 + -6

-4 + -6 = -10

4) Finally, the absolute value of -10 is 10

Therefore the answer is 10

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Answer:

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Step-by-step explanation:

step by step explanation

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Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:

aev [14]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&J&(~ 0 &,& 2~) 
% (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2} \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}$