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Aleks04 [339]
3 years ago
12

Review the graph. On a coordinate plane, a vector has origin (6, 2) and terminal point (0, 4). What is the component form and ma

gnitude of the vector shown? LeftAngleBracket negative 2, 7 RightAngleBracket and StartRoot 53 EndRoot LeftAngleBracket negative 2, 7 RightAngleBracket and 53 LeftAngleBracket negative 7, 2 RightAngleBracket and StartRoot 53 EndRoot LeftAngleBracket negative 7, 2 RightAngleBracket and 53
Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer:

I think C

Step-by-step explanation:

slavikrds [6]3 years ago
6 0

Answer:

It is C

Step-by-step explanation:

just took test edge2020, i got it right

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What is the product? (X^4)(3x^3-2)(4x^2+5x)
Paha777 [63]

Given expression: (x^4)(3x^3-2)(4x^2+5x).

We need to simplify the given expression by multiplying.

\mathrm{Expand}\:\left(3x^3-2\right)\left(4x^2+5x\right):\quad 12x^5+15x^4-8x^2-10x

=\left(x^4\right)\left(12x^5+15x^4-8x^2-10x\right)

\left(x^4\right)\left(12x^5+15x^4-8x^2-10x\right):\quad 12x^9+15x^8-8x^6-10x^5

=12x^9+15x^8-8x^6-10x^5

<h3>Therefore, \left(x^4\right)\left(3x^3-2\right)\left(4x^2+5x\right)=\quad 12x^9+15x^8-8x^6-10x^5..</h3>
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