Um when doing this, there is no defined b term yet--b is unknown still. So it would be y= 2x+b. Then you have to plug (1,2) in as x and y, and solve for b. Once you get the answer for b, you put it into your equation and have your answer. But saying you want y=2x-3 to pass through (1,2) is impossible unless it already passes through it since all of the terms are already definite and put into place so they can't be changed.
Answer:
$13.05
Step-by-step explanation:
The prize will be $13.05 after the discount.
29x45%=13.05
OR
29x0.45=13.05
Answer:
F(x)=
+7cosh(x)+C
Step-by-step explanation:
The function is f(x)=3ˣ+7sinh(x), so we can define it as f(x)=g(x)+h(x) where g(x)=3ˣ and h(x)=7sinh(x).
Now we have to find the most general antiderivative of the function this means that we have to calculate
wich is the same as
The sum rule in integration states that the integral of a sum of two functions is equal to the sum of their integrals. Then,
=
1- ![\int\ {g(x)} \, dx =](https://tex.z-dn.net/?f=%5Cint%5C%20%7Bg%28x%29%7D%20%5C%2C%20dx%20%3D)
this is because of the rule for integration of exponencial functions, this rule is:
, in this case a=3
2-![\int\ {h(x)} \, dx =](https://tex.z-dn.net/?f=%5Cint%5C%20%7Bh%28x%29%7D%20%5C%2C%20dx%20%3D)
, number seven is a constant (it doesn´t depend of "x") so it "gets out" of the integral.
The result then is:
F(x)=
![\int\ {(h+g)(x)} \, dx=\int\ {h(x)} \, dx +\int\ {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cint%5C%20%7B%28h%2Bg%29%28x%29%7D%20%5C%2C%20dx%3D%5Cint%5C%20%7Bh%28x%29%7D%20%5C%2C%20dx%20%2B%5Cint%5C%20%7Bg%28x%29%7D%20%5C%2C%20dx)
The letter C is added because the integrations is undefined.