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ladessa [460]
3 years ago
6

Given f(x) = x2 + 4, g(x) = x −5

Mathematics
1 answer:
podryga [215]3 years ago
8 0

Answer:

3 men at 7 hours per day complete flooring of 84 m in 2 days. how many men can floor 256 m in 4 days working 8 hours brainly

Step-by-step explanation:

3 men at 7 hours per day complete flooring of 84 m in 2 days. how many men can floor 256 m in 4 days working 8 hours brainly

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Find the value of x in the equation below. 60 = 10 x​
Ede4ka [16]

Answer:

Just do 60 divided by 10

Step-by-step explanation:

60=10 x  10 times 6 = 60 so x=6

7 0
3 years ago
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Solve for x. PLEASE HELP ASAP WILL GIVE BRAINLIEST ANSWER
murzikaleks [220]

Answer:

x = 2.6  

Step-by-step explanation:

To find x, you need to find how many times you need to multiply 25 to get 65. Using reverse operations will make this easier. 65 / 25 = 2.6. We can check this by multiplying 25 by 2.6, and we get 65.

3 0
3 years ago
Find the slope of the line that passes through (4,2) and (4,5)
Hunter-Best [27]

Answer: Undefined

Step-by-step explanation:

(slope = m)

m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{4-4}=\frac{3}{0}

(3 divided by 0 is undefined, so the slope is undefined)

4 0
3 years ago
Which rectangle will have the largest area?
slavikrds [6]

Answer: l = 4 cm, w = 7 cm

Step-by-step explanation:

i think that this is it

4 0
3 years ago
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5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio
kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85°  below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component  Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy =  -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = \sqrt{Vx^{2} + Vy^{2}  }

==> \sqrt{15.83^{2} + 14.79^{2}  } = <em>21.66 knot</em>

<em></em>

direction of boat = tan^{-1} \frac{Vy}{Vx}

==> tan^{-1} \frac{14.79}{15.83} = <em>43.05°</em>

3 0
3 years ago
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