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Yakvenalex [24]
3 years ago
10

Please help me what is the answer?​

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

I guess 4

Step-by-step explanation:

4

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Find the domain of the following piecewise function
r-ruslan [8.4K]

The domain of the function will be [-4, 6). Then the correct option is B.

The complete question is attached below.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The function is given below.

f(x) = \left\{\begin{matrix}x+4, & if & -4\leq x < 3 \\\\2x-1, & if & 3 \leq x < 6 \\\end{matrix}\right.

Then the domain of the function will be [-4, 6).

Then the correct option is B.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

6 0
2 years ago
Sketch the vectors u and w with angle θ between them and sketch the resultant.
Rama09 [41]

Given:

Two vectors (u) and (w) and the angle between them θ

\begin{gathered} |u|=50 \\ |w|=12 \\ \theta=35\degree \end{gathered}

the sketch of the vectors will be as shown in the following figure:

As shown, the resultant vector is the blue line segment

The vector R has a magnitude = 60.22

And the angle between u and R = 5.56°

8 0
1 year ago
20,000 pounds equals how many English tons?
bagirrra123 [75]
Let's remember that 1 pound equals 0.0005 tons, so if we multiply 0.0005 x 20,000 the answer is 10, so 20,000 pounds equal 10 tons.
7 0
3 years ago
Algebra- systems of equations (x,y)<br> 3x + 4y = 56<br> x = 3y + 12
ElenaW [278]

Answer:

2

Step-by-step explanation:

simplify......dndjddjejdjdjehdeww

7 0
3 years ago
Help with some math homework? The area of a triangle is 110 square inches. the height of the triangle is 8 less than 3 times its
Alenkasestr [34]
A = h x b; where A = area of a triangle; h = height of the triangle; b = base of the riangle;
So, we have the equation : 110 = (3b - 8)b;
We solve the equation 3b^2 - 8b - 110 = 0;
The positiv solution  is b = 7.53 cm;
h = 3 x 7.53 - 8;
h = 14.59 cm;
3 0
3 years ago
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