Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57

5 0

3 years ago

The airplane Li’s family will be flying on can seat up to 149 passengers. If 96 passengers are currently on the plane, which ine

Ivenika [448]

For this case, the first thing you should do is define a variable.
We have then:
x: number of passengers remaining who can board the plane.
We have as data:
1) They can board up to 149 passengers
2) There are 96 passengers currently aboard.
Writing inequality we have:
$x + 96 \leq 149
$
Answer:
An inequality that can be used to determine how many more people can board is:
$x + 96 \leq 149$

3 0

3 years ago

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Please help me what is the answer?​

Please help me what is the answer?