The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x)
Substitute in for them. Y+2=3/5(X-10)
Answer: For the first part, her total savings would be $88, and for the second part, (let's pretend s = the total savings) the equation would be s = 40 + w x 6.
Step-by-step explanation: As for the first part, we would need to multiply her money per week times the amount of weeks she works. We can do this by simply multiplying the amount she makes (6) by the amount of weeks she works (8), resulting in 48, but we still have to add that number to the amount she already has, or 40, making $88 in total, as for the second part, this does a great job of explaining the reasoning behind that as well. Hope this answered your question!
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
D) 50ft
Step-by-step explanation:
(18×x) + (32×18) + [(48-18-18)×(32-11)]
= 1728
18x + 576 + (12×21) = 1728
18x = 1728 - 828
18x = 900
x = 50
