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Mamont248 [21]
3 years ago
5

Find the sixth term of the geometric sequence whose common ratio is 1/3 in whose first term is eight

Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer:

8/243

Step-by-step explanation:

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Answer:

0.5 hours

Explanation:

Given:

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2 years ago
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Step-by-step explanation:

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3 years ago
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When a fraction of 12 is taken away from 17, what remain exceed one-third of seventeen by six.
vova2212 [387]
X - the fraction

17- 12x=\frac{1}{3} \times 17+6 \\
17-12x=\frac{17}{3}+6 \\
-12x=\frac{17}{3}+6-17 \\
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-12x=\frac{17}{3}-\frac{33}{3} \\
-12x=-\frac{16}{3} \\
x=-\frac{16}{3} \times (-\frac{1}{12}) \\
x=\frac{16}{36} \\
x=\frac{4}{9}

The fraction is 4/9.
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3 years ago
A pipe is 36 feet long. It needs to be cut into pieces that are each 3/4 feet long. How many pieces can be made from the pipe?
Ket [755]

108/4 = 27 pieces you multiply 36 x 3 = 108 and the denominator stays the same so 108/4 equals to 27 pieces

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Consider the diagram. What is the length of segment AB?
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B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks. 
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3 years ago
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