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Kobotan [32]
3 years ago
11

2) Find the unknown sizes.

Mathematics
2 answers:
Kaylis [27]3 years ago
4 0

Answer:

hope this helps, happy learning!!!

Akimi4 [234]3 years ago
3 0

I have shoot it . so, hope this help u.

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A rectangular flower garden in samanthas backyard has 180 ft around its edge. the width of the garden is 40 ft.what is the lengt
sasho [114]
Given is,
the total edges= 180 ft
width= 40 ft
so, 40 ft minus from 180 fts
total edge-width= length
180ft -40 ft= length
140ft = length
6 0
3 years ago
If x3=-27 then what is x?
Rasek [7]
The answer would be 9! 3 x 9 = 27.
5 0
4 years ago
Read 2 more answers
Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h
irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = <u><em>population proportion.</em></u>

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, H_0 : p = 0.70      {means that the population proportion is equal to 0.70}

Alternate Hypothesis, H_A : p < 0.70      {means that the population proportion is less than 0.70}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                           T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion = 0.63

            n = sample of observations = 100

So, <u><em>the test statistics</em></u>  =  \frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }

                                     =  -1.528

The value of z-test statistics is -1.528.

<u>Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.</u>

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0
3 years ago
Estimate the closest to the actual value of (2.9983) · (1.8792)<br> to the nearest tenths place.
Fantom [35]

Answer:

3 & 2

Explanation:

7 0
3 years ago
Read 2 more answers
For his car Jason paid 91.48 per speacker for 3 speackers and 92.55 per tire for 5 tires with 8 100 bills . How much did Jason g
Svetach [21]

Answer:

1 speaker is $91.48

3 speakers = $91.48 × 3

= $274.44

1 tire is 9$2.55

5 tires = $92.55 × 5

= $462.75

8, 100 bills = $800

The cost for the 3 speakers and 5 tires = $274.44 + $462.75

= $737.19

Therefore, the change that Jason got was = $800 - $737.19

= $62.81

5 0
3 years ago
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