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2 years ago

1. What is the value of n in -57 - n = -144? A-201 B-87 C 87 D 201

Mathematics

2 answers:

ss7ja [257]2 years ago

8 0

It’s 24.20 I took this quiz

Dahasolnce [82]2 years ago

5 0

Answer:

C=87

Step-by-step explanation:

To isolate the variable, you need to take away -57 by adding it to -144.

Then, you'd see:

-n=-87

Next, you divide both sides by -1 to get 87

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Multiply by 3, then subtract 4.

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Answer:

what number do you want to "Multiply by 3, then subtract 4."

Example:

(12 x 3) - 4

36 - 4 = 32

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3 years ago

The left and right page numbers of an open book are two consecutive integers whose sum is 229

alukav5142 [94]

Answer:

114, and 115

Step-by-step explanation:

114+115 = 229

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2 years ago

Read 2 more answers

The transformation T = [0 1 -1 0] is applied the figure below.

Margaret [11]

Answer:

<h2>a.) reflect across x-axis</h2>

Step-by-step explanation:

The transformation described is about multiplying the vertical value by -1:

$(x,y) \implies (x,-y)$

That means all vertical coordinates will change to the opposite side, but all horizontal coordinates will maintain at the same coordinate.

As a result, we'll have a reflection across the x-axis, because the y coordinates were transformed.

Therefore, the right answer is A.

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3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago

here are 1515 people in an office with 55 different phone lines. If all the lines begin to ring at once, how many groups of 55 p

Mashcka [7]

Answer:

360,360 groups of 5 people.

Step-by-step explanation:

We have been given that there are 15 people in an office with 5 different phone lines. We are asked to find groups of 5 people that can answer these lines, if all the lines begin to ring at once.

We will use fundamental principle of counting to solve our given problem.

There are 15 people to answer 1st line, that will leave us with 14 people to answer 2nd line.

Now, we will have 13 people to answer 3rd line, that will leave us with 12 people to answer 4th line.

There are 11 people to answer 5th call.

So 5 lines can be answered in $15\times 14\times 13\times 12\times 11=360,360$ ways.

Therefore, 360,360 groups of 5 people can answer these lines.

6 0

2 years ago