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Bas_tet [7]
3 years ago
9

What is the slope of the line that goes through points (−3,−4) and (−7,16)? please help

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

5

Step-by-step explanation:

slope = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}

The second y point is 16 and the first is -4, so:

(16) - (-4)

Which can be written as 16 + 4 because a double negative makes a positive. Do the same for the x points, -7 and -3:

(-7) - (-3)

(-7) + (3)

Now solve both of them:

16 + 4 = 20

(-7) + 3 = -4

Remember, the slope formula is y over x, so we still need to put it into the fraction form:

\frac{20}{-4}

You can reduce this to -\frac{5}{1}, or 5.

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Answer:

10) 51°

11) 152

Step-by-step explanation:

10) 42 + 9 = 51

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3 years ago
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-4(2x + 4) > 8x + 64
romanna [79]

Hello there I hope you are having a great day :)

Your Question, -4(2x + 4) > 8x + 64 Solve for X

1) Expand -8x-16>8x+64

2) Add 16 to both sides -8x-16+16>8x+64+16

3) Simplify -8x>8x+80

4) Subtract 8x from both sides -8x-8x>8x+80-8x

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6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)

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5 0
2 years ago
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olya-2409 [2.1K]

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3 years ago
Find the slope of a line parallel to y=(2/5)x + (4/5)
Tcecarenko [31]

Answer:

So if a line was parallel it would have same slope. You can search up what slope-intercept form means. But if you have an equation like this:

y = mx+b

The slope will be m. Your question is written in the form. 2/5 = m.

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