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leonid [27]
3 years ago
5

-8+(-6)= -14 in words

Mathematics
2 answers:
Nata [24]3 years ago
5 0

Answer:

Negative eight plus negative six equals negative fourteen

lora16 [44]3 years ago
4 0

Answer:

Negative 8 plus negative 6 equals negative fourteen.

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Tom earned $72 walking dogs for 6 hours. How many total hours will it take tom to earn $96 in all? Solve using unit rates
slava [35]

Answer:

8 hours

Step-by-step explanation:

Step one:

Given data

Tom earned $72 walking dogs for 6 hours

amount earned = $72

time taken = 6 hours

Required

The time taken to earn $96

Step two:

let us find the unit rate of his earning

unit rate = 72/6

= 12 per hour

 

In 1 hour Tom earns $12

in x hours he will earn $96

cross multiply we have

96*1= 12x

divide both sides by 12

x= 96/12

x=8 hours

3 0
3 years ago
What do you do first to graph the equation? 3x - 2y = 8​
kolezko [41]

Answer:

Figure out the x and y intercepts.

Step-by-step explanation:

you should find what the y or x intercept's are.

To figure that out you need to divide the number next to x or y to 8. use x to find out x intercept and y for y intercept.

lets find out y intercept

8 / -2 = -4

and now x intercept

8 / 3 = 1.75 or 1 (3/4)

Once you found out the intercepts you can now graph the equation.

8 0
3 years ago
Consider the planes 4x+3y+4z=1 and 4x+4z=0. (A) Find the unique point P on the y−axis which is on both planes. ( 0 equation edit
Nana76 [90]

Answer:

Step-by-step explanation:

A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,

1=4x+3y+4z = 3y + (4x+4z)= 3y+0.

From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).

B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.

\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k

As we want a unit vector, we must calculate the modulus of u:

|u|=\sqrt{12^2+0^2+12^2} = \sqrt{2\cdot 12^2}=12\sqrt{2}.

Thus, the wanted vector is \frac{u}{12\sqrt{2}}. Therefore,

u = \frac{1}{\sqrt{2}}i-\frac{1}{\sqrt{2}}k = \frac{\sqrt{2}}{2}i-\frac{\sqrt{2}}{2}k.

C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.

r = \frac{1}{3}j +\lambda \left( \frac{\sqrt{2}}{2}i- \frac{\sqrt{2}}{2}k \right)

where \lambda is a real number.

8 0
4 years ago
Lydia writes the equation below with a missing value
skelet666 [1.2K]
The answer is C bc y=5x is a direct variation
6 0
3 years ago
Given the revenue function R(x)= 100x −2x^2 (space) 1 ≤ x ≤ 30 and the cost function C(x)= 500 + 9x for a company, find the prof
ziro4ka [17]

well, once you take in all the Revenue from sales, and subtract all the costs that went in for the product, what's leftover is the Profit.

so then, profit P(x), is simply the revenue minus costs, namely P(x) = R(x) - C(x)

R(x)=100x-2x^2\hspace{5em}C(x)=500+9x \\\\\\ P(x)=(100x-2x^2)~~ - ~~(500+9x)\implies P(x)=91x-2x^2-500 \\\\\\ \stackrel{\textit{at a production of 25 units, x =25}}{P(25) = 91(25)-2(25)^2-500}\implies P(25)=\stackrel{2275-1250-500}{525}

3 0
2 years ago
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