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3 years ago

If the hemisphers has a radius of 3 feet, how many cubic feet of water can the water tank hold?

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

Answer:

$volume \ of \ hemisphere = \frac{2}{3} \pi r^3 = \frac{2}{3}\pi \cdot (3)^3 = \frac{2}{3} \pi 27 = 2\pi \cdot9 = 18\pi cubicfeet$

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Pachacha [2.7K]

Answer:

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3 years ago

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neonofarm [45]

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2 years ago

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Strike441 [17]

Answer:

$a = 6\sqrt 3,\:\:b =12,\:\:c=6\sqrt 2$

Step-by-step explanation:

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3 years ago

Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Gnoma [55]

Sum/difference:

Let

$x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}$

This means that

$3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}$

Now, assume that $x$ is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that $x$ was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

$x = -15\sqrt{8}$

if again we assume x to be rational, we have

$\sqrt{8} = -\dfrac{x}{15}$

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

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3 years ago