<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
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The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Answer:
C
Step-by-step explanation:
Answer: 64
Step-by-step explanation: 4 to the 3rd means 4 times itself three times.
So we have 4 · 4 · 4 which is 64.
Minimum=25
first quartile= 30
Third quartile=45
Maximum=55
Since 10 only has one 0 you would just add 0 at the end of your number. giving you 8050 which is eight thousand fifty
