Comparing the temperature of a coolant before and after use in a machining process.
Step-by-step explanation:
The temperature of a coolant in the polar region was found to be modeled by the equation t=(8x-55)° where t is the final fluid temperature after being used for cooling ,x is the time the fluid is applied on the cutting edge and -55 is the normal temperature of the fluids used for cooling processes in a machine garage.
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Integers :brainly.com/question/102082
Keyword : integer
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Answer:
Step-by-step explanation:
lets look at the numbers
38-19=19
57-38=19
76-57=19
aₙ=aₙ-₁ +19
Area = (x+6)(x+2) = x^2 + 8x + 12
Answer:
6
Step-by-step explanation:
From the Trapezoid attached :
EF = GT
FG = LA
LE = AT = 10
LA = 24 ; FG = 24
FG + EF + GT = 40
Let : EF and GT = x
FG + 2x = 40
24 + 2x = 40
2x = 40 - 24
2x = 16
x = 16 ÷ 2 = 8
Hence, EF = GT = 8
Using Pythagoras :
Opposite² = hypotenus² - Adjacent²
LF² = LE² - FE²
LF² = 10² - 8²
LF² = 100 - 64
LF² = 36
LF = √36
LF = 6