Step-by-step explanation:
Total Surface area of a pyramid is given as
= Lateral surface area + area of base.
Lateral surface area = 1/2×perimeter of base×slant height
given the base is square with side 9 in , and slant height of 12 inches.
therefore, LSA = 1/2(9*4)×12 = 216 in^2
Now, TSA = LSA + Base area = 216+9^2 = 297 in^2
a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).
b) It can not be solved as dimensions are missing in the question.
However, the logic has been explained in the soluion one easily put values to find the solution.
Answer:
see explanation
Step-by-step explanation:
Calculate C by adding corresponding components of A + B
C = ![\left[\begin{array}{ccc}4\\-7.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C-7.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-2.5\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2.5%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-2.5\\-7.5+5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-2.5%5C%5C-7.5%2B5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1.5\\-2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%5C%5C-2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
14.7x + 4x = 0*(49y+39y) y = 14
18.7x = 0(686 + 546)
18.7x = 0
x = 0
Answer:
210
Step-by-step explanation:
you can do 200 + 10 = 210
You can also do 200 + 1 x10
