Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
Answer:
Option C, both functions have an y-intersect equal to 2.
Step-by-step explanation:
When we have a function f(x), the y-intercept is the value f(0). This is the point where the graph of the function intersects the y-axis.
Then, for f(x) = -x^2 + 5*x + 2
The y-intercept is:
f(0) = -0^2 + 5*0 + 2 = 2
f(0) = 2
And for g(x) we do not have the equation, but we have the graph, so we can just look at which value of y does the graph intersects the y-axis.
We can see that the graph intersects the graph at y = 2
Then the y-intersect is: g(0) = 2
So both functions have the same y-intersect. Then the correct option is C.
45
1080 divided by 24
45
45 5lbs per hour
If you let x = 13:
Then, Area = 2(13)^2 - 5(13)
= 338 - 65
= 273 sq ft
If you let 2x-5 = 13:
2x = 18
x = 6
Then, Area = 2(6)^2 - 5(6)
= 72 - 30
= 42 sq ft
Therefore, your options are A or C. Your answer can be chosen based on what you assume the width to be. Good luck!
Answer: x^2 +6x +2x +36 = X^2 +8x + 36
Step-by-step explanation:
