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crimeas [40]
3 years ago
10

What to sides must be congruent

Mathematics
2 answers:
devlian [24]3 years ago
6 0
Where is the problem so i can answer
harkovskaia [24]3 years ago
3 0

Answer:

When a triangle has two congruent sides it is called an isosceles triangle

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent

Step-by-step explanation:

I'm not sure what you are looking for so here

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If angle a measures 64 then what does angle b measure?
Naddik [55]

Answer:

b = 26°

Step-by-step explanation:

a ; b = complementary =>

a + b = 90°  } => b = 90° - 64° = 26°

a = 64°

8 0
3 years ago
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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

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How to turn an a equation from standard form into vertex form
alekssr [168]

Is this a real question?

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10x10x10x10x10x10x10 in word form
Vsevolod [243]

Answer:

10,000,000

Step-by-step explanation:

ten million

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S the given number a solution of the equation? c = 2c – 4; 8
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10 I think..I might be wrong
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