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Stella [2.4K]
2 years ago
12

Suppose that the world's current oil reserves is R = 1820 billion barrels. If, on average, the total reserves

Mathematics
1 answer:
iVinArrow [24]2 years ago
3 0

Answer:

A. R = -18t + 1,820

B. 1,568 billions of barrels

C. approximately 101.11 years

Step-by-step explanation:

To make our equation, we'll use the form R = mt + b. M represents how many billion barrels of oil are being lost each year, which we know is 18 billion. So -18 will be our m. B is how many total barrels of oil there are, which is 1,820. So 1,820 will be our b. Now the equation looks like this:

R = -18t + 1,820

We can use this equation to answer Part B.

Replace the t with 14:

R = -18(14) + 1,820

Now solve for R:

R = -18(14) + 1,820

R = -252 + 1,820

R = 1,568

14 years from now, there will be 1,568 billions of barrels left.

To solve part C, we need to find how many years it will take for all of the oil to be used up. After it's all used up, the total amount of oil will be 0, so we can replace R with 0 and then solve for t:

0 = -18t + 1,820

Subtract 1,820 from both sides to isolate -18t:

0 - 1,820 = -18t + 1,820 - 1,820

-1,820 = -18t

Divide both sides by -18 to isolate the t:

-1,820/-18 = -18t/-18

101.11 = t

After approximately 101.11 years, all of the oil will be used up.

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Answer:

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 0.895, \sigma = 0.292, n = 37, s = \frac{0.292}{\sqrt{37}} = 0.048

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This is the pvalue of Z when X = 0.809.

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{0.809 - 0.895}{0.048}

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