Which expression calculates the speed in meters per second of an object that travels a distance of 40 m every 10 s?

Let’s work with some actual data this time. Go online to research and find a set of real-world data in two variables. The data c

slega [8]

The quadratic regression equation that best fits the data set is y = 32.86x² - 379.14x + 1369.14

<h3>The data points </h3>

The following table of values represents the data points that would be used to solve this question:

x 3 4 5 6 7 8 9

y 470 416 403 226 314 338 693

Where:

x represents years since 2000
y represents the annual revenue of a manufacturing company in thousand dollars

<h3>The function of the dataset</h3>

The table of values illustrates a quadratic function.

The function would be calculated using a graphing calculator

From the graphing calculator, we have:

a = 32.86; b = -379.14 and c = 1369.14

A quadratic regression equation is represented as:

y = ax² + bx + c

So, we have:

y = 32.86x² - 379.14x + 1369.14

Hence, the quadratic regression equation that best fits the data set is y = 32.86x² - 379.14x + 1369.14

<h3>Why the function type was chosen?</h3>

From the table of values in (a), we can see that as x increases; the value of y decreases and then increases after it reaches a minimum.

This illustrates the behavior of a quadratic regression function

See attachment for the scatter plot

Read more about quadratic regression equation at:

brainly.com/question/14786188

#SPJ1

5 0

1 year ago

50 points ! marking brainly to whoever gets all 5 correct !

Svetradugi [14.3K]

1. 5

2. 7-3 root 3

3. 6

4. 4.24

5. 5.76

3 0

2 years ago

An athlete knows that when she jogs along her neighborhood greenway, she can complete the route in 10 minutes. It takes 20 minu

IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking rate, so athlete's jogging speed would be $x+5$ miles per hour.

$\text{Distance}=\text{Rate}\cdot \text{Time}$

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get $D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}$

$D_{\text{walking}}=\frac{x}{3}$

While jogging, we will get $D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}$

$D_{\text{jogging}}= \frac{(x+5)}{6}$

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

$\frac{x}{3}=\frac{x+5}{6}$

Cross multiply:

$6x=3x+15$

$6x-3x=15$

$3x=15$

$\frac{3x}{3}=\frac{15}{3}\\\\x=5$

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: $x+5\Rightarrow 5+5=10$

Therefore, athlete's jogging speed is 10 miles per hour.

3 0

2 years ago

Marie currently has a collection of 58 stamps if she buys s stamps each week for w Weeks which expression represents the total n

laila [671]

58 stamps is the number she gets each week. So if she went for one week, 58*1=58. 58*2=116 and so on. Because we don't know the exact number of weeks, we say 58w or 58*w because you multiply however many number of weeks she collects.

8 0

2 years ago

Need help now please

baherus [9]

Answer:

2

Step-by-step explanation:

rise over run = y/x

3/1.5= 2

8 0

2 years ago