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Len [333]
3 years ago
5

Can you please help me with this​

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

Dot plot

Step-by-step explanation:

Each dot on on 0.84 represents each plane. 5 planes had a average cruising speed of 0.84.

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PLZ HELP I WILL MARK BRAINLIEST
s344n2d4d5 [400]

Answer:

the purpose of this as is to get everyone excited about the roller coaster

Step-by-step explanation:

3 0
3 years ago
Factor f(x) = 4x3 + 15x2 – 24x + 5 into linear factors given that - 5 is a zero of f(x).15f(x) = 4x3 + 15x2 - 24x + 5 =(Factor c
Basile [38]

If x=-5 is a zero, then the first factor of the polynomial would be (x + 5 )

To find the other two factors we can divide the polynomial by the expression (x+5).

Using synthetic division, we have:

-5 I 4 15 -24 5 (Coefficients of the dividend)

I -20 25 -5 (Multiplying each coefficient by the results of the substraction and adding)

-----------------------------------------------------------------------------------

4 -5 1 0 (Coefficients of the quotient)

The result of the division is 4x^2 - 5x + 1. Factoring it, we have:

4x^2 - 4x -x + 1 (Separating -5x into -x and -4x)

4x (x - 1) - (x -1) (Factoring each pair of terms)

(x-1)(4x-1) (Factoring using the common factor)

So the answer would be:

(x + 5 )(x-1)(4x-1)

3 0
1 year ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
1
Gnoma [55]

Answer:

A

Step-by-step explanation:

edge

3 0
3 years ago
Can someone help me with this?
zvonat [6]
Sorry, don't have time to do them right now but I know who does!

http://www.wolframalpha.com/widgets/view.jsp?id=ae438682ce61743f90d4693c497621b7

Just plug in 2 at a time.
4 0
3 years ago
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