Answer:
See below.
Step-by-step explanation:
The circumstance is that the circle started out as a sphere. It was taking a walk down the street. A piano fell on it, squashed it, and it became a circle.
Answer:
Option B and C are correct.
Step-by-step explanation:
Inverse function: If both the domain and the range are R for a function f(x), and if f(x) has an inverse g(x) then:
for every x∈R.
Let 
and 
Use logarithmic rules:
then, by definition;
= 
Similarly;
for 
and 
then, by definition;
= 
Similarly,
g(f(x)) = x
Therefore, the only option B and C are correct. As the pairs of functions are inverse function.
<h3>Answer:</h3>
133 ft
<h3>Step-by-step explanation:</h3>
Given in the question,
length of the rectangle = 31 ft
width of the rectangle= 20 ft
diameter of semicircle = 20 ft
radius of semicircle = 20/2 ft = 10 ft
<h3>Formula to use:</h3>
perimeter of rectangle + perimeter of semicircle
perimeter of rectangle = 2(l+w)
perimeter of semicircle = 1/2(2πr)
<h3>Plug values in the formula above</h3>
2(31 + 20) + 3.14(10)
133.4 ft
≈ 133 ft
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
12^2=144
144 is divided by b which also is an odd interger, there only 2 numbers : 1 and 3
if b=3, a^2=48, then there will be no a available
if b=1 , a^2=144, then a is 12 and 12 can not be divided by 9
The answer is D
