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3 years ago

Will someone help me work through this problem, please

Mathematics

1 answer:

Ainat [17]3 years ago

6 0

Step-by-step explanation:

Radius (r) = 2 ft

V = 4/3 × 22/7 × (2)³

= 4/3 × 22/7 × 8

= 33.52 ft³

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5(3a-1)-2(3a-2)=3(a+2)+v

STatiana [176]

Answer:

The answer is option C. 6a-7

Step-by-step explanation:

Given that

5(3a-1)-2(3a-2)=3(a+2)+v

Solve for v

∴ v = 5(3a-1)-2(3a-2) - 3(a+2)

∴ v = 15a - 5 - 6a + 4 - 3a - 6

∴ v = 15a - 6a - 3a - 5 + 4 - 6

∴ v = 6a - 7

So the answer is option C. 6a-7

5 0

3 years ago

Find the missing measurements. Area: ? Length: 13 cm Width: 15 cm

Shalnov [3]

Answer:

13 x 15 = 195

4 0

3 years ago

How to solve 3/2=2x this problem

poizon [28]

Step-by-step explanation:

3/2 is 1½ so that means 1½ divided by 2 is 3/4

3 0

3 years ago

A square pyramid with a height of 7 inches has a volume of 47.25 cubic inches. Find the side length of the square base.

Romashka [77]

Answer:

4.5 inches

Step-by-step explanation:

volume= 1/3 (base area) × height

47.25= 1/3 ( base area) × 7

20.25 = base area

now since the base is a square we can evaluate base area = length²

20.25= length²

length = 4.5 inches

5 0

3 years ago

Multiply the polynomials. (x – 5)(x2 + 4x – 2)

klemol [59]

the cheap answer is simply

(x-5)(x²+4x-2)

we can simply multiply the terms on one by the terms of the other and then add like-terms and simplify.

$\bf (x-5)(x^2+4x-2)\implies \begin{array}{cllll} x^2+4x-2\\ \times x\\ \cline{1-1}\\ x^3+4x^2-2x \end{array}+ \begin{array}{cllll} x^2+4x-2\\ \times -5\\ \cline{1-1}\\ -5x^2-20x+10 \end{array} \\\\\\ x^3+4x^2-2x-5x^2-20x+10\implies x^3+4x^2-5x^2-2x-20x+10 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-22x+10~\hfill$

6 0

3 years ago

Read 2 more answers