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guajiro [1.7K]
3 years ago
9

Question Help

Mathematics
1 answer:
ioda3 years ago
4 0

Answer:

8,600 acres are old growth treees

Step-by-step explanation:

Here's The answer have a great day ♡ :)

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How many time does 8 go into 27
iogann1982 [59]
It is: 27/8 = 3 with a remainder of 3


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4 years ago
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Find the slope and the y intercept
Eva8 [605]

Answer:

So the slope is -1 and the y-intercept is 4

Step-by-step explanation: I really hope this helps!

4 0
3 years ago
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What is the largest number you can form from the numbers $2,5,8,9,10$ and the operations $\times,+,+,-$, and exactly one pair of
Levart [38]

Answer:

The largest number is 218.

Step-by-step explanation:

The given numbers are 2,5,8,9,10, given operations are ×,+,+,- and exactly one pair of parentheses.

We need to find the largest number which can be form by using given information.

We know that multiplication of two lager numbers is greater than their addition.

We need to multiply 10 and sum of 9,8,5. To get the largest number we have subtract the smallest number.

So, the largest possible number is defined by the expression

10\times (9+8+5)-2

10\times (22)-2

220-2

218

Therefore, the largest number is 218.

6 0
3 years ago
3. Samuel tiene 11 cajas con mosaicos cuadrados de 20 cm por
mihalych1998 [28]

Answer:

Primero veamos el área de la pared, es decir, el área total que Samuel debe cubrir.

La pared es de 3m por 2m.

Entonces el area es:

A = 3m*¨2m = 6m^2.

Ahora veamos los mosaicos.

Cada mosaico es un cuadrado de 20cm por 20cm.

El primer paso sería cambiar las unidades para tener metros aca también.

1cm = 0.01m

entonces.

20cm = 20*0.01m = 0.2m.

Entonces cada mosaico es:

0.2m por 0.2m

El área de cada mosaico es:

a = 0.2m*0.2m = 0.04m^2.

En una caja de mosaicos hay 14 mosaicos, entonces con una caja Samuel puede cubrir 14 veces a, o:

14*0.04m^2 = 0.56m^2.

Y Samuel tiene 11 cajas, entonces tenemos 11 veces lo de arriba:

11*0.56m^2 = 6.16m^2.

Y el área de la pared es 6m^2.

6.16m^2 > 6m^2

Entonces con las 11 cajas de mosaicos podemos cubrir completamente esa pared, y vamos a tener algunos mosaicos sobrantes.

Entonces Samuel no debe comprar mas cajas.

6 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce
storchak [24]

Answer:

The correct answer will be "60 min/hour".

Step-by-step explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t = \frac{1}{3}

v(0)=30

v(\frac{1}{3})=50

For MVT,

v'(c)=\frac{v(\frac{1}{3} -v(0))}{(\frac{1}{3} )}

       =\frac{20}{\frac{1}{3} }

       =60 \ min/hour

5 0
3 years ago
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