Question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acceleration is exactly 60 mi/h2.

Answer 1

Answer:

The correct answer will be "60 min/hour".

Step-by-step explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t = $\frac{1}{3}$

$v(0)=30$

$v(\frac{1}{3})=50$

For MVT,

$v'(c)=\frac{v(\frac{1}{3} -v(0))}{(\frac{1}{3} )}$

       $=\frac{20}{\frac{1}{3} }$

       $=60 \ min/hour$