Answer:
<u> The following four traits are -: </u>
- <u>Pedigree 1 -</u> A recessive trait (autosomal recessive) is expressed by pedigree 1.
- <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
- <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
- <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.
Explanation:
<u>Explaination of each pedigree chart</u>-
- Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected.
In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa) - <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (
) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical
must be contributed by II-6. - The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
- <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.
In the question the pedigree chart was missing ,hence it is given below.
Answer: Experience 1 is the one that has the greatest reliability.
Explanation: Because of this potential variation, biological experiments need to have a large sample size and preferably be repeated several times. With more samples and repeating the experiment more often, the probability of arriving at a wrong conclusion due to random variation is diminished. As experience 1 has had several repetitions, it is the experience with a more reliable result.
Answer:
(08) and (32)
Explanation:
To make osmosis happen there has to be a difference in the concentration of solutes, between the inside and the outside of the cell. To valance this difference in concentration, water has to flow towards a place that has a higher number of solutes.
The lipids in the cell's wall make this membrane semipermeable. This allows the passage of specific components only, such as water through aquaporins. Lipids and other elements are of importance in the barrier because they maintain the cell separated from the outside, allowing it to be balanced as regards the different substances that can interact with it.
Yes it is necessary for the production of apt in your cells because apt needs oxygen to form correctly.
<u>"</u><u><em>False" because the pure substances are made up of single elements or compounds.</em></u><u> </u>Hope this helps! Thank you for posting your question at here on Brainly. Have a great day! -Charlie