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Alex73 [517]
3 years ago
8

PICTURE IS PROVIDED SO PLEASE LOOK AT IT AND THEN ANSWER

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

43 square cm

Step-by-step explanation:

Hope that helps!

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Help plz I’m not good at this
Natalka [10]

Answer:

<u>The correct answer is A. 1/8</u>

Step-by-step explanation:

<u>Let's solve (1/3 * 9/16) / 1 1/2 = x</u>

(1/3 * 9/16) / 1 1/2 = x

9/48 / 1 1/2 = 9/48 * 2/3 = 18/144

18/144, we can simplify dividing by 18 at the numerator and the denominator, this way:

x = 18 ÷ 18/ 144 * 18 = 1/8

<u>The correct answer is A. 1/8</u>

4 0
3 years ago
1/5r+ 8/15 when r=1/3
ZanzabumX [31]

Answer:

3/5

Step-by-step explanation:

1/5r + 8/15

~Substitute

1/5(1/3) + 8/15

~Simplify

1/15 + 8/15

~Add

9/15

~Simplify

3/5

Best of Luck!

5 0
3 years ago
When I count as a principal of $1000 and earns 4% simple interest per year and other account as a principal $1000 and earns 4% i
OLga [1]

Answer: the account that earned compound interest has the greater balance at the end of four years.

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the amount invested.

P represents the principal or amount invested.

R represents interest rate

T represents the duration of the investment in years.

From the information given,

P = 1000

R = 4%

T = 4 years

I = (1000 × 4 × 4)/100 = 160

Total amount earned is

1000 + 160 = $1160

The formula for determining compound interest is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 1000

r = 4% = 4/100 = 0.04

n = 1 because it was compounded once in a year.

t = 4 years

Therefore,.

A = 1000(1+0.04/1)^1 × 4

A = 1000(1.04)^4

A = $1170

3 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
Which of the following arguments correctly justifies the second step of the flow proof of the triangle angle sum theorem below
pochemuha
We need to see the second step of the proof, so we know what needs to be justified. It would also be nice to see the list of answer choices. I'll never understand how someone who can't answer the question and has to ask someone else can then go ahead and decide that the person helping him only needs to see parts of the question.
8 0
3 years ago
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