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katrin [286]
3 years ago
10

The diagram shows a right-angled triangle.

Mathematics
1 answer:
Margarita [4]3 years ago
6 0
1/sin(38)*7=11.4
Hope it helps
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Can i please get some help
STALIN [3.7K]

Answer: number 5 is A number 6 is B

Step-by-step explanation:

8 0
3 years ago
What is the y-intercept of y=10x+7?explain pls and pls don't spam random words
andreev551 [17]

Answer:

7

Step-by-step explanation:

Since this equation is already in slope intercept form you can see its 7.

The formula: y=mx+b is a formula to identify the slope and y-intercept.

The m indicates the slope and the b indicates the y-intercept.

4 0
3 years ago
Given that the value of m+n=-2, find the value of 4m+4n-3.​
nikklg [1K]

Answer:

-11

Step-by-step explanation:

m + n = - 2

4(m + n) = - 2(4) (multiplying both sides by 4)

4m + 4n = - 8

4m + 4n - 3 = - 8 - 3 (Subtracting 3 from both sides)

4m + 4n - 3 = - 11

6 0
3 years ago
Read 2 more answers
A school reserved a banquet hall for the spring dance. In addition to a $100 deposit, each couple must pay $20. If the total cos
AnnZ [28]

Step-by-step explanation:

1.)20x + 100 = 1440

-Let the number of couples be x. So, the total amount paid by all the couple’s are $20x. School paid $100 as security, so the total amount paid is

$ (20x + 100)

2.) 20x = 1440 - 100 ⇒ 20x = 1040

X = 52

3. ) The security money  is $100, so the couples paid $1440- 100 = $1040 in total. As the couples paid $ 20 each than- \frac{1040}{20} = 52

5 0
3 years ago
The U.S. National Highway Traffic Safety Administration gathers data concerning the causes of highway crashes where at least one
ZanzabumX [31]

Answer:

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932

Step-by-step explanation:

P(BAC=0|Crash with fatality)=0.625

P(BAC is between .01 and .09|Crash with fatality)=0.302

P(BAC is greater than .09|Crash with fatality)=0.069

Let the event of BAC = 0 be X

Let the event of BAC between 0.01 and 0.09 be Y

Let the event of BAC greater than 0.09 be Z

Let the event of a crash with at least one fatality = C

P(X|C) = 0.625

P(Y|C) = 0.302

P(Z|C) = 0.069

P(C) = 0.028

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)

But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by

P(Z|C) = P(Z n C)/P(C)

P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932

Hope this Helps!!!

8 0
3 years ago
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