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katrin [286]
3 years ago
10

The diagram shows a right-angled triangle.

Mathematics
1 answer:
Margarita [4]3 years ago
6 0
1/sin(38)*7=11.4
Hope it helps
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Jarvis has the following averages in his math
ollegr [7]

Answer:

≈77

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo.

My answer:

Given:

  • Homework Avg: 93
  • Quiz Avg: 84
  • Test Avg: 72
  • Final Exam: 60

and weights Homework at 20%, Quizzes at 30%, Tests at 40%, and the final exam at 10%

=>Jason's class average is:

=  80*20% + 84*30%+74*40%+60*10%

=  80*0.2 + 84*0.3+74*0.4+60*0.1

= 76.8

≈77

8 0
3 years ago
Read 2 more answers
What value of x solves the equation 56/x = 8 (Trigonometry)<br><br> (In image)
Feliz [49]

Answer:

b. 7

\frac{56}{x}  = 8 \\ 8x = 56 \\ x = 7

6 0
3 years ago
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Please help me guysssssssssss I need help.......... Assignment due in 30 MIN!!!!! 1 PIC ATTACHED
MAVERICK [17]
The tool is easy to use. All you need to do is choose the number of words you want to create (the default is five, but you can input any number you'd like) and the type of words you want. You can choose from all words, verbs only, nouns only or adjective only depending on which best meets your needs.
5 0
3 years ago
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How do I solve this equation?
Keith_Richards [23]

Answer:

y=\frac{7}{2}x+11

Step-by-step explanation:

To solve, we need to find the y-intercept (b). In order to find the y-intercept, we can plug in the slope and the (x,y) coordinate pair given to us into the equation to solve for the y-intercept:

y=mx+b

4=(-7/-2)*-2+b

4=14/-2+b

4=-7+b

Add 7 to both sides

b=11

Therefore the equation is:

y=\frac{7}{2}x+11 (note that the fraction is positive since the two negatives cancel out)

4 0
2 years ago
A ball is thrown straight up with a initial velocity of 56 feet per second . The height , h , of the ball t seconds after it is
Tju [1.3M]

<span>Formula: H(t) = 56t – 16t^2   </span>

H(t) = - 16t^2 + 56t

<span><span>A.      </span>What is the height of the ball after 1 second? H (1) = 56(1) – 16(1) ^2 = 40 pt.</span>

<span><span>B.      </span>What is the maximum height? X = - (56)/2(- 16) = 1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>

<span><span>C.      </span><span>After how many seconds will it return to the ground? – 16t^2 + 56t = 0   - 8t =0 t = 0</span></span>

<span><span>-          </span><span>8t (2 + - 7) = 0     2t – 7 = 0  t = 7/2   Ans: 3.5 seconds</span></span>

3 0
3 years ago
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