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3 years ago

11

riverside and mount pleasant are 16 km from each other.How far apart would the cities be on a map that has a scale of 1 cm:8 km?

1 answer:

sergeinik [125]3 years ago

3 0

If you multiply the scale by 2 you would get 2 cm:16 km. So the answer would be 2 cm

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The graph of the function B is shown below. If B(x) = -1, then what is x?

GREYUIT [131]

The answer is c, 2.To find this, look on the graph for a point with the y value of -1. (2,-1) is the solution.

3 0

3 years ago

Read 2 more answers

Find the value of x, y, and z in the parallelogram below.

telo118 [61]

The values of x, y, and z of the parallelogram are -19°, -115° and 27°

<h3>What is a parallelogram?</h3>

A parallelogram is a two-dimensional geometrical shape whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length. The Sum of adjacent angles of a parallelogram is equal to 180 degrees.

for a parallelogram opposite angles are equal

-4x -1 = 75

-4x = 76

x = 76/-4

x = -19°

sum of adjacent angles are supplementary

(-y-10) + 75 = 180

-y + 65 = 180

-y = 180 - 65

-y = 115

y = -115°

Also

4z - 3 + 75 = 180

4z + 72 = 180

4z = 180 - 72

4z = 108

z = 108/4

z = 27°

In conclusion, the values of x = -19, y = -115, z = 27

Learn more about Parallelogram: brainly.com/question/20526916

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8 0

1 year ago

Write an equation of the line that passes through the point (5, -8) with slope 5

Oxana [17]

$\Large\texttt{Answer}$

$equation=$ $\bold{y=5x-33}$

$\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$

$\Large\texttt{Process}$

<em>⇨ Use the formula below</em>

<em /> $\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}$

<em>⇨ Substitute the parameters:</em>

<em />

<em /> $\bold{y-(-8)=5(x-5)}$

$\bold{y+8=5x-25}$

$\bold{y=5x-33}$

Hope that helped

4 0

2 years ago

Hey what's the answer<br>thanks. <br>

k0ka [10]

Step-by-step explanation:

if b+c=0

b=-c

x^b=x^-c

so

1/[2(x^b)+1]

6 0

3 years ago

Quadrilateral ABCD?<br>

Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = $\sqrt{(7 - 2)^{2} + (4 - 4)^{2} }$

⇒ AD = $\sqrt{5^{2} }$

⇒ AD = 5

DC = $\sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }$

⇒ DC = $\sqrt{5^{2} }$

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = $\sqrt{(-2 - 2)^{2} + (-5 - 4)^{2} }$

⇒ AB = $\sqrt{(-4)^{2} + (-9)^{2} }$

⇒ AB = $\sqrt{16 + 81}$

⇒ AB = $\sqrt{97}$

BC = $\sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2} }$

⇒ BC = $\sqrt{9^{2} + 4^{2} }$

⇒ BC = $\sqrt{81 + 16}$

⇒ BC = $\sqrt{97}$

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

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6 0

1 year ago