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3 years ago

Xcube + 4x+2 divisible by x+2

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

8 0

It’s not divisible because there’s a remainder.

kenny6666 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

note : let f(x) = x^3 +4x+2 is not divisible because :

f(-2) = (-2)^3 +4(-2)+2 = -14≠0 (you have the raimned

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8 p varies directly as the square root of q. p = 8 when q = 25. Find p when q = 100.

Lostsunrise [7]

Answer:

Step-by-step explanation:

p=k√q

8=k√25

8=k5

k=8/5

p when q=100

p=8/5*√100

p=8/5*10

p=16

4 0

3 years ago

Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams

Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0

3 years ago

C x 34 = Show Your work

Brut [27]

Answer:

C x 34 or 34c

Step-by-step explanation:

There isn't really a way to show work or really an answer unless you have a value for C but I hope this helped anyway.

3 0

3 years ago

Read 2 more answers

X²-2x=8 what is the answer

katrin2010 [14]

Answer:

X=4, -2

Step-by-step explanation:

Check attachment

6 0

3 years ago

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

enyata [817]

Answer:

a) Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0

4 years ago