The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
12/x+5
x represents “a number” because it’s unknown and the + sign is because the words sum
If you already have an equation, all you have to do is locate the slope and look after it. But if it's in a graph, it's where the line is crossing the y-axis.
An example of the equation would be
y=2x+3
y=mx+b
2 would be m which is slope
and 3 would be b which is the y-intercept
Answer:
9) y = -3x - 4
10) y = -1/3x + 14/3
11) y = x - 1
12) y = -7/5x - 18/5
13) y = 3/5x + 9/5
14) y = -2x - 3
Step-by-step explanation:
For this explanation, let's use the last problem as the example. You would use the formula y=mx+b. The first thing you would need to find would be the slope, or m. So, you would find the slope and conclude the answer is -2. After that, you would solve for b and get the answer. Hope this helped!