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ExtremeBDS [4]
2 years ago
8

How many licks does it take to get to the center of a tootsie pop

Mathematics
2 answers:
drek231 [11]2 years ago
4 0

Answer:

it depends on the lick but it's usually around 35 to 100 licks

Natasha2012 [34]2 years ago
3 0

Answer:

364 licks to get to the center of a tootsie pop.

Explanation:

Purdue University engineering students stated that their licking machine, which was fashioned after a human tongue, took an average of 364 licks to reach the core of a Tootsie Pop. Twenty members of the group took on the licking challenge on their own, averaging 252 licks each to the center.

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I need help with these three problems please​
Liono4ka [1.6K]

Answer:

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

34^{2}  =  {x}^{2}  +  {x}^{2}  \\ 2 {x}^{2}  = 1156 \\  {x}^{2}  = 1156 \div 2 \\  {x}^{2}  = 578 \\ x =  \sqrt{578}  \\

Thus, the perimeter of the square is

= 4( \sqrt{578} ) \\  = 96.2 ft\:  \:  \: (3 \: s.f.)

Q9. Equilateral triangles have 3 equal sides and each interior angle is 60°.

Since the perimeter of the equilateral triangle is 126cm,

length of each side= 126÷3 = 42 cm

The green line drawn in picture 3 is the altitude of the triangle.

Let the altitude of the triangle be x cm.

sin 60°= \frac{x}{42}

\frac{ \sqrt{3} }{2}  =  \frac{x}{42}  \\ x =  \frac{ \sqrt{3} }{2}  \times 42 \\ x = 21 \sqrt{3}  \\ x = 36.4

(to 3 s.f.)

Therefore, the length of the altitude of the triangle is 36.4cm.

4 0
3 years ago
Read 2 more answers
Can anybody teach me how to solve this pls​
wel
Answer is 10 and 170, complementary angles are 90°, while supplementary angles are 180 in total, if angle A is 80 then you subtract 90 by 80 and you get 10, so that is angle B, So then you are asked what is angle C. Which is part of the supplementary angle so you take the 10° that you got from B and then you subtract 180 by the 10, And thats how you get 170 and that's how you know that C is 170 (hope this explanation helps)
3 0
3 years ago
What is the slope-intercept form of the equation of the line with the slope of -5/8 that passes through the point (-14,6)
inessss [21]

Step-by-step explanation:

y-y1 = m(x-x1) is the equation for a linear line in y=mx+b (slope intercept)

slope = m = -5/8

x1 = -14

y1 = 6

y-6 = -5/8 (x--14)

y-6 = -5/8 (x+14)

y-6 = -5/8x-70/8

y-48/8= -5/8x-70/8

y = -5/8x - 22/8

When x = 0, y = -22/8, which makes (0, -22/8) your y intercept

5 0
3 years ago
Work out an equation of the straight line with gradient 3 that passes through the point with coordinates (2, 4).
Gnom [1K]

Answer:

The answer is

\huge \boxed{y = 3x - 10}

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (2, 4) and the slope is 3

The equation of the line is

y - 4 = 3(x - 2) \\ y + 4 = 3x - 6 \\ y = 3x - 6 - 4

We have the final answer as

y = 3x - 10

Hope this helps you

3 0
3 years ago
The length of a rectangular photo is 1 centimeter less than three times its width. If the area of the photo is 102 square centim
noname [10]

Answers:

  • Length = 17
  • Width = 6

======================================================

How to get those answers:

Let w be the unknown width in centimeters. This variable is some positive real number. This means w > 0 which will be useful later.

The length is "1 cm less than 3 times its width" and it tells us the length is defined by the expression 3w-1. Whatever w is, we triple it to get 3w and then subtract 1 to get the final length.

Multiply the length and width to get the area 102

length*width = area

(3w-1)*w = 102

3w^2-w = 102

3w^2-w-102 = 0

We could guess and check our way to factoring this, but that's not very efficient. The quadratic formula is the better option. It may seem a bit messy, but it's a more direct path that doesn't involve guessing.

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-102)}}{2(3)}\\\\w = \frac{1\pm\sqrt{1225}}{6}\\\\w = \frac{1\pm35}{6}\\\\w = \frac{1+35}{6}\ \text{ or } \ w = \frac{1-35}{6}\\\\w = \frac{36}{6}\ \text{ or } \ w = \frac{-34}{6}\\\\w = 6\ \text{ or } \ w \approx -5.667\\\\

We ignore the second solution (w = -5.667 approximately) because we stated earlier that w > 0. In other words, a negative length does not make sense, so that's why we ignore it.

-----------------

If w = 6 cm is the width, then 3w-1 = 3*6-1 = 18-1 = 17 cm is the length.

Note that length*width = 17*6 = 102 which is the proper area we want. This confirms the answers.

6 0
3 years ago
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