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Gre4nikov [31]
3 years ago
13

Can somebody plz answer this math problem correctly thanks!!

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

33. 224

34. 128

35. 244

36. 160

Step-by-step explanation:

:)

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Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)
Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

x^2-2x + y^2 - 6y = 26

Typically, the equation of a circle would be in the form (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.

To get the given equation x^2-2x + y^2 - 6y = 26 into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

x^2-2x

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

x^2-2x+1

Great! Now, let's add this to our original equation:

x^2-2x+1+y^2-6y = 26

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27

Complete the square:

(x-1)^2+y^2-6y = 27

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation (x-1)^2+y^2-6y = 27:

y^2-6y

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

y^2-6y+9

Great! Now, back to our original equation:

(x-1)^2+y^2-6y+9= 27

Remember to add 9 on the other side as well:

(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36

Complete the square:

(x-1)^2+(y-3)^2= 36

<u>3) Determine the center and the radius</u>

(x-1)^2+(y-3)^2= 36

(x-h)^2+(y-k)^2=r^2

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

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Answer:

Step-by-step explanation:

is C  -1/2

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Step-by-step explanation:

Sorry if it is wrong

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7% of her paycheck was spent on the gift~
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