In standard form it would be y= 5x - 4
Answer:
3(6) -1
------------
2(6)+1
Step-by-step explanation:
first find r(6)
r(6) =3(6) -1
= 18 -1
Then find s(6)
s(6) = 2(6)+1
Then divide
r(6)/s(6) = 3(6) -1
------------
2(6)+1
7/4=1.75
1.75=175%
175% of a school year is 7 quarters.
Answer:
2x+50 and 5x-55 both are congruent or have same measure.
Step-by-step explanation:
Since we want to prove that both lines are parallel, this means no theorems that involve with parallel lines apply here.
First of, we know that AC is a straight line and has a measure as 180° via straight angle.
x+25 and 2x+50 are supplementary which means they both add up to 180°.
Sum of two measures form a straight line which has 180°.
Therefore:-
x+25+2x+50=180
Combine like terms:-
3x+75=180
Subtract 75 both sides:-
3x+75-75=180-75
3x=105
Divide both sides by 3.
x=35°
Thus, x = 35°
Then we substitute x = 35 in every angles/measures.
x+25 = 35°+25° = 60°
2x+50 = 2(35°)+50° = 70°+50° = 120°
5x-55 = 5(35°)-55 = 175°-55° = 120°
Since 2x+50 and 5x-55 have same measure or are congruent, this proves that both lines are parallel.
Answer:
B. -1
Step-by-step explanation:
x^3-4x^2+2x+10=x^2-5x-3
We know it has 3 roots since it is a 3rd degree polynomial.
Two of the roots are (3+2i) and (3-2i)
Subtract x^2-5x-3 from both sides
x^3-4x^2+2x+10-(x^2-5x-3)=x^2-5x-3 -(x^2-5x-3)
Distribute the minus sign
x^3-4x^2+2x+10-x^2+5x+3=x^2-5x-3 -x^2+5x+3
x^3 -5x^2+7x +13 =0
Graphing this equation , we see that it crosses the x axis at x=-1
That covers the three roots, 1 real and two complex
