Pls help me with this

Tara wants to fix the location of a mountain by taking measurements from two positions 3 miles apart. From the first position, t

Black_prince [1.1K]

Answer:

Shortest distance from the mountain is 3.17 miles.

Step-by-step explanation:

From the figure attached,

Let a mountain is located at point A.

Angle between the mountain and point B (∠B) = 53°

Angle between the mountain and point C (∠C) = 78°

Distance between these points = 3 miles

Since, m∠A + m∠B + m∠C = 180°

m∠A + 53° + 78° = 180°

m∠A = 180°- 131° = 49°

By applying sine rule in triangle ABC,

$\frac{\text{sin}(49)}{BC}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}= \frac{\text{sin}(78)}{AB}$

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(53)}{AC}$

AC = $\frac{3\text{sin}(53)}{\text{sin}(49)}$

AC = 3.17 miles

$\frac{\text{sin}(49)}{3}=\frac{\text{sin}(78)}{AB}$

AB = $\frac{3\text{sin}(78)}{\text{sin}(49)}$

AB = 3.89 miles

Therefore, shortest distance from the mountain is 3.17 miles.

7 0

3 years ago

Solve, using linear combination. 3x – y = 4 2x + y = 6

BlackZzzverrR [31]

X=2
y=2
hope this helps
ps. tiger algebra is a really good website!

5 0

3 years ago

Do the lengths 60,80,100 form a right triangle

Lapatulllka [165]

Answer:

100 Sq. =80 SQ. +60 SQ.

10000=6400+3600

10000=10000

yes,given length can form right angle triangle.

6 0

3 years ago

Which is the best estimate for 49% of 598 A. 3 B.30 C.300 D.3,000

DIA [1.3K]

Answer:

300

Step-by-step explanation:

3 would be extremely low

30 would be low

300 would be about right

3,000 lets not talk about this

Hope this helps

7 0

3 years ago

Read 2 more answers

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de

Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

$\to df = n - 1 = 71-1= 70$

In point B:

$\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5$

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

$\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832$

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

$\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\$

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

$\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816$

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

$\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\$

5 0

3 years ago