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lora16 [44]
2 years ago
6

Write an equation (any form) for the quadratic graphed below. Y=

Mathematics
1 answer:
Licemer1 [7]2 years ago
4 0

Answer:

y = -2x^2 - 4x - 1

Step-by-step explanation:

We can see that the graph passes through (-2, -1), (-1, 1) and (0, -1).

Let's solve

ax^2 + bx + c = y

a(-2)^2 + b(-2) + c = -1

4a - 2b + c = -1

a(-1)^2 + b(-1) + c = 1

a - b + c = 1

a0^2 + b0 + c = -1

c = -1

we got c = -1 so we input it into the other 2

4a - 2b - 1 = -1

4a - 2b = 0

2a - b = 0

2a = b

a - b - 1 = 1

a - b = 2

a = b + 2

Let's input b = 2a

a = 2a + 2

-a = 2

a = -2

b = 2a = 2*(-2) = -4

c = -1

y = -2x^2 - 4x - 1

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Answer:

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Step-by-step explanation:

Just to make things easy, let's name the points A(3,9) B(5,9) C(3, 3) and D(5, 3).

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Distance formula is sqrt((x1 - x2)^2 + (y1 - y2)^2) = d.

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The distance of points A and B is 2 units, and B to D is 6 units, multiply both by 2, (2*2=4, 6*2=12) and add the values to find 16 units.

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3 years ago
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