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galina1969 [7]
4 years ago
12

Over a 5-day period. the value of a stock has a total change of -4.35. What was the average change per day?

Mathematics
1 answer:
UNO [17]4 years ago
6 0
-.87 hope this helps :)
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DaniilM [7]

Answer:

An independent clause is a group of words that contains both a subject and a predicate. It expresses a complete thought and can stand alone as a sentence. It can also be joined to other dependent or independent clauses to make a more interesting and complex sentence.Step-by-step explanation:

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3 years ago
How to get 14 using four fours
Len [333]

Answer:

14

Step-by-step explanation:

4 \times (4 - .4) -. 4

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3 years ago
Take a deck of playing cards form following sets out of those
swat32

The information given about the probability shows that the cardinality of D is 18.

<h3>How to calculate the probability?</h3>

From the complete information, the number of red-colored cards is 26.

Also, the number of red-colored number cards will be 18.

The cardinality of a set is a measure of a set's size, meaning the number of elements in the set.

Here, the cardinality of set D is 18.

Here is the complete question:

Take a deck of playing cards. Form following sets out of those:

A = Set of Face Cards

B = Set of Red Coloured Face cards

C = Set of Black Coloured Face Cards

D = Set of Red Coloured Number Cards

Find the Cardinality of set D

Learn more about probability on:

brainly.com/question/24756209

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7 0
2 years ago
34.1 divided by what equals 22
allochka39001 [22]
I hope this helps you

3 0
3 years ago
Read 2 more answers
How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i
zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

\dbinom 31 \dbinom 32 = 3\cdot3 = 9

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

\dbinom 33 \dbinom 30 = 1\cdot1 = 1

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}

where we use the binomial identity

\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n

3 0
1 year ago
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