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3 years ago

Please help me. Algebra.

Mathematics

1 answer:

otez555 [7]3 years ago

7 0

Answer:

!!thanks for the pionts and have terrible day!!

Step-by-step explanation:lol

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Help me !!!!!!!!!!!!!???

Nesterboy [21]

Answer:

what are you supposed to be doing

7 0

2 years ago

Read 2 more answers

Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plu

Lostsunrise [7]

The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given as follows:

$(f \circ g)(x) = f(g(x))$

In this problem, the functions are:

$f(x) = \frac{1}{x - 3}$ .

$g(x) = \sqrt{x + 3}$

The composite function is of the given functions f(x) and g(x) is:

$f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}$

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

$x + 3 \geq 0$

$x \geq -3$

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

$\sqrt{x + 3} - 3 \neq 0$

$\sqrt{x + 3} \neq 3$

$(\sqrt{x + 3})^2 \neq 3^2$

$x + 3 \neq 9$

$x \neq 6$

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

7 0

1 year ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .