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Komok [63]
2 years ago
5

Background info-A rabbit started at point 0 and made 3 jumps: a jump of 4 units, then a jump of 2 units, and then a jump of 1 un

it. We do not know the direction of either jump. Where on the number line can this rabbit be now? The answer to this is -7, - 5, - 3, - 1, 1, 3, 5, and 7
Actual question-Next time, the rabbit from the previous problem started at 10. Where on the number line can he be after the same three jumps?
Mathematics
1 answer:
Kipish [7]2 years ago
5 0

Answer:

im confused

Step-by-step explanation:

i hope you find the answer tho

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Joseph has started completing the square on the equation 3x^2-7x+12=0. He has worked to the point where he has the expression x^
Dima020 [189]
Starting with <span>3x^2-7x+12=0, we divide all four terms by 3, resulting in the following factored form:
</span><span>
3(</span><span>x^2-[7/3]x+4)=0.
</span><span>
Since 3 cannot equal 0, we can focus on the following:

x^2 - 7/4 x =-4

This completes the assignment (describe Joe's steps up to this point).



If you wish to go further:

Next, take HALF of the coefficient of x and square your result:

(-7/[4][2])^2 = 49/64

Add this to both sides of </span>x^2 - 7/4 x =-4:    <span>x^2 - 7/4x + 49/64 =-4+49/64

Rewrite the left side as (x-7/8)^2 and the right side as 49/64 - 256/64

Simplify the right side by combining these terms:  -207/64

Then x-7/8 = plus or minus (1/8)sqrt(-207)

Next, x = 7/8 plus or minus (1/8)*i*</span>√207, or

          7 plus or minus i*√207
 x = ----------------------------------
                         8
4 0
3 years ago
If a line of type measures 5 inches (12.5 centimeters) in length, how many picas long is it
Kryger [21]
It would be 30 picas

6 0
3 years ago
I'm just confused on all of it
balandron [24]
Let's solve for x.<span><span><span>3x</span>+<span>4y</span></span>=36</span>Step 1: Add -4y to both sides.<span><span><span><span>3x</span>+<span>4y</span></span>+<span>−<span>4y</span></span></span>=<span>36+<span>−<span>4y</span></span></span></span><span><span>3x</span>=<span><span>−<span>4y</span></span>+36</span></span>Step 2: Divide both sides by 3.<span><span><span>3x</span>3</span>=<span><span><span>−<span>4y</span></span>+36</span>3</span></span><span>x=<span><span><span><span>−4</span>3</span>y</span>+12</span></span>Answer:<span>x=<span><span><span><span>−4</span>3</span>y</span>+<span>12

i got dis

</span></span></span>
4 0
3 years ago
Solve the inequality 48 –16<br> B.<br> x &gt; 16<br> C.<br> x &lt; –16<br> D.<br> x &lt; 16
pogonyaev

Step-by-step explanation:

48-16 is not an inequality,it's a simple subtraction operation. Please check and come again

3 0
2 years ago
In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is
VladimirAG [237]

Answer:

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean \overline x = 960 hours

Sample size n = 36

Mean population \mu = 937

Standard deviation \sigma = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}

Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}

Z = \dfrac{23}{8.66}

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0
3 years ago
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