I can't see all the triangles, but basically, it is asking you to write down triangles that are congruent with each other.
The marks in the corner of the triangle indicate that the angles of that triangle are congruent to the other triangle.
So,
Triangle NOP= Triangle NQP
Make sure that the points align with each other, otherwise you could be saying that two different triangles are congruent to each other.
N= N O=Q P=P
I hope this cleared some confusion!
~kaikers
In this case the temperature depends on the hour. So temperature is your X and hour is your Y variable. When h=0, x=0. So the 21*C is you x=0 or y-int point.
If we are trying to match the equation for a line of y=mx+b, 21*C=b.
Our rate of change is -4*C/h, which is our m variable.
So y=(-4)x+(21)
OR in this case, t=-4h+21.
Answer D.
Answer:
See below. No image this time.
Step-by-step explanation:
1.
- P(2, 8) → P'(-5, 1), which it went 7 units to the left, and 7 units down. Here is the equation: (x - 7, y - 7).
2.
- R(-4, -9) → R'(-4, -2), which went 7 units up. Here is the equation: (x, y + 7).
3.
- M(10, -3) → M'(3, 4), which went 7 units left, 7 units up. Here's the equation: (x - 7, y + 7).
4.
- K(7, 11) → K'(0, 11), which went 7 units left. Here is the equation: (x - 7, y).
Answer:
you know it is when you can't solve it any further. If the numbers cannot be divided by a common number. there is no possible way to make it any more compacted.
Step-by-step explanation:
Answer:
Let's call:
f = price of 1 cup of dried fruit
a = price of 1 cup of almonds
In order to build the linear system, you need to consider that the total price of a bag is given by the sum of the price of cups times the number of cups in each bag, therefore:
Solve for a in first equation:
a = (6 - 3f) / 4
Then substitute in the second equation:
41/2 f + 6 · (6 - 3f) / 4 = 9
41/2 f + 9 - 9/2 f = 9
16 f = 0
f = 0
Now, substitute this value in the formula found for a:
a = (6 - 3·0) / 4
= 3/2 = 1.5
Hence, the cups of dried fruit are free and 1 cup of almond costs 1.5$
Step-by-step explanation:
